Solution 1.2:2d - Revision history

Tek at 12:21, 22 September 2008

2008-09-22T12:21:15Z

←Older revision		Revision as of 12:21, 22 September 2008
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	the expression can be written as		the expression can be written as

-	{{Displayed math\|\|<math>\frac{1}{5\cdot 3\cdot 3}+\frac{1}{3\cdot 5\cdot 5}</math>}}	+	{{Displayed math\|\|<math>\frac{2}{3\cdot 3\cdot 5}+\frac{1}{3\cdot 5\cdot 5}</math>}}

	and then we see that the denominators have <math>3\cdot 5</math> as a common factor. Therefore, if we multiply the top and bottom of the first fraction by 5		and then we see that the denominators have <math>3\cdot 5</math> as a common factor. Therefore, if we multiply the top and bottom of the first fraction by 5
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	{{Displayed math\|\|<math>\begin{align}		{{Displayed math\|\|<math>\begin{align}
-	\frac{2}{5\cdot 3\cdot 3}\cdot \frac{5}{5}+\frac{1}{3\cdot 5\cdot 5}\cdot	+	\frac{2}{3\cdot 3\cdot 5}\cdot \frac{5}{5}+\frac{1}{3\cdot 5\cdot 5}\cdot
-	\frac{3}{3} &=\frac{2}{5\cdot 3\cdot 3\cdot 5}	+	\frac{3}{3} &=\frac{2}{3\cdot 3\cdot 5\cdot 5}
	+\frac{3}{3\cdot 5\cdot 5\cdot 3}\\[10pt]		+\frac{3}{3\cdot 5\cdot 5\cdot 3}\\[10pt]
	&= \frac{10}{225}+\frac{3}{225}\,\textrm{.}\\		&= \frac{10}{225}+\frac{3}{225}\,\textrm{.}\\

Tek at 07:52, 19 September 2008

2008-09-19T07:52:42Z

←Older revision		Revision as of 07:52, 19 September 2008
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	If we divide up the denominators into their smallest possible integer factors,		If we divide up the denominators into their smallest possible integer factors,

-		+	{{Displayed math\|\|<math>\begin{align}
-	<math>\begin{align}	+	45&=5\cdot 9=5\cdot 3\cdot 3\,, \\
-	& 45=5\~~centerdot~~ 9=5\~~centerdot~~ 3\~~centerdot~~ 3 \\	+	75&=3\cdot 25=3\cdot 5\cdot 5\,, \\
-	& 75=3\~~centerdot~~ 25=3\~~centerdot~~ 5\~~centerdot~~ 5 \\	+	\end{align}</math>}}
-	\end{align}</math>	+
-		+

	the expression can be written as		the expression can be written as

		+	{{Displayed math\|\|<math>\frac{1}{5\cdot 3\cdot 3}+\frac{1}{3\cdot 5\cdot 5}</math>}}

-	~~<math>\frac{1}{5\centerdot 3\centerdot 3}+\frac{1}{3\centerdot 5\centerdot 5}</math>~~	+	and then we see that the denominators have <math>3\cdot 5</math> as a common factor. Therefore, if we multiply the top and bottom of the first fraction by 5
-		+	and the second by 3, the result is the lowest possible denominator
-	and then we see that the denominators have	+
-	<math>3\~~centerdot~~ 5</math>	+
-	as a common factor. Therefore, if we multiply the top and bottom of the first fraction by	+
-	~~<math>~~5~~</math>~~	+
-	and the second by	+
-	~~<math>~~3~~</math>~~	+
-	, the result is the lowest possible denominator.	+
-		+
-		+
-	~~<math>\begin{align}~~	+
-	~~& \frac{2}{5\centerdot 3\centerdot 3}\centerdot \frac{5}{5}+\frac{1}{3\centerdot 5\centerdot 5}\centerdot \frac{3}{3} \\~~	+
-	~~& \\~~	+
-	~~& =\frac{2}{5\centerdot 3\centerdot 3\centerdot 5}+\frac{3}{3\centerdot 5\centerdot 5\centerdot 3} \\~~	+
-	~~& \\~~	+
-	~~& =\frac{10}{225}+\frac{3}{225} \\~~	+
-	~~\end{align}</math>~~	+
-		+

		+	{{Displayed math\|\|<math>\begin{align}
		+	\frac{2}{5\cdot 3\cdot 3}\cdot \frac{5}{5}+\frac{1}{3\cdot 5\cdot 5}\cdot
		+	\frac{3}{3} &=\frac{2}{5\cdot 3\cdot 3\cdot 5}
		+	+\frac{3}{3\cdot 5\cdot 5\cdot 3}\\[10pt]
		+	&= \frac{10}{225}+\frac{3}{225}\,\textrm{.}\\
		+	\end{align}</math>}}

-	The lowest common denominator is	+	The lowest common denominator is 225.
-	~~<math>~~225~~</math>~~	+
-	.	+

Ian at 12:52, 11 September 2008

2008-09-11T12:52:34Z

←Older revision		Revision as of 12:52, 11 September 2008
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	<math>\begin{align}		<math>\begin{align}
	& \frac{2}{5\centerdot 3\centerdot 3}\centerdot \frac{5}{5}+\frac{1}{3\centerdot 5\centerdot 5}\centerdot \frac{3}{3} \\		& \frac{2}{5\centerdot 3\centerdot 3}\centerdot \frac{5}{5}+\frac{1}{3\centerdot 5\centerdot 5}\centerdot \frac{3}{3} \\
		+	& \\
	& =\frac{2}{5\centerdot 3\centerdot 3\centerdot 5}+\frac{3}{3\centerdot 5\centerdot 5\centerdot 3} \\		& =\frac{2}{5\centerdot 3\centerdot 3\centerdot 5}+\frac{3}{3\centerdot 5\centerdot 5\centerdot 3} \\
		+	& \\
	& =\frac{10}{225}+\frac{3}{225} \\		& =\frac{10}{225}+\frac{3}{225} \\
	\end{align}</math>		\end{align}</math>
		+

Ian at 12:45, 11 September 2008

2008-09-11T12:45:57Z

←Older revision		Revision as of 12:45, 11 September 2008
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-	{{~~NAVCONTENT_START~~}}	+	If we divide up the denominators into their smallest possible integer factors,
-	<~~center~~> ~~[[Image:1_2_2d~~.~~gif]]~~ </~~center~~>	+
-	{{~~NAVCONTENT_STOP~~}}	+
		+	<math>\begin{align}
		+	& 45=5\centerdot 9=5\centerdot 3\centerdot 3 \\
		+	& 75=3\centerdot 25=3\centerdot 5\centerdot 5 \\
		+	\end{align}</math>
		+
		+
		+	the expression can be written as
		+
		+
		+	<math>\frac{1}{5\centerdot 3\centerdot 3}+\frac{1}{3\centerdot 5\centerdot 5}</math>
		+
		+	and then we see that the denominators have
		+	<math>3\centerdot 5</math>
		+	as a common factor. Therefore, if we multiply the top and bottom of the first fraction by
		+	<math>5</math>
		+	and the second by
		+	<math>3</math>
		+	, the result is the lowest possible denominator.
		+
		+
		+	<math>\begin{align}
		+	& \frac{2}{5\centerdot 3\centerdot 3}\centerdot \frac{5}{5}+\frac{1}{3\centerdot 5\centerdot 5}\centerdot \frac{3}{3} \\
		+	& =\frac{2}{5\centerdot 3\centerdot 3\centerdot 5}+\frac{3}{3\centerdot 5\centerdot 5\centerdot 3} \\
		+	& =\frac{10}{225}+\frac{3}{225} \\
		+	\end{align}</math>
		+
		+
		+	The lowest common denominator is
		+	<math>225</math>
		+	.

Tekbot: Lösning 1.2:2d moved to Solution 1.2:2d: Robot: moved page

2008-09-09T08:17:23Z

Lösning 1.2:2d moved to Solution 1.2:2d: Robot: moved page

←Older revision

Revision as of 08:17, 9 September 2008

Tekbot: Robot: Automated text replacement (-[[Bild: +[[Image:)

2008-08-21T06:25:49Z

Robot: Automated text replacement (-[[Bild: +[[Image:)

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2008-03-26T09:59:47Z

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