http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-ImperialCollege/index.php?action=history&feed=atom&title=Image%3A1_2_1d.gifImage:1 2 1d.gif - Revision history2026-04-08T17:27:15ZRevision history for this page on the wikiMediaWiki 1.11.1http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-ImperialCollege/index.php?title=Image:1_2_1d.gif&diff=4375&oldid=prevIan at 12:04, 11 September 20082008-09-11T12:04:27Z<p></p>
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<td colspan='2' style="background-color: white; color:black;">←Older revision</td>
<td colspan='2' style="background-color: white; color:black;">Revision as of 12:04, 11 September 2008</td>
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<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>When we have three fractions involved in an addition, we need to multiply the top and bottom of each fraction by the product of the other fraction's denominators so that all fractions have a common denominator,</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td></tr>
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<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><math>\frac{1\centerdot 4\centerdot 5}{3\centerdot 4\centerdot 5}+\frac{1\centerdot 3\centerdot 5}{4\centerdot 3\centerdot 5}+\frac{1\centerdot 3\centerdot 4}{5\centerdot 3\centerdot 4}=\frac{20}{60}+\frac{15}{60}+\frac{12}{60}</math></div></td></tr>
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<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>When all three fractions have a common denominator, they can easily be added up</div></td></tr>
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<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><math>\frac{20}{60}+\frac{15}{60}+\frac{12}{60}=\frac{20+15+12}{60}=\frac{47}{60}</math></div></td></tr>
</table>Ianhttp://wiki.sommarmatte.se/wikis/2009/bridgecourse1-ImperialCollege/index.php?title=Image:1_2_1d.gif&diff=329&oldid=prevLina at 09:49, 26 March 20082008-03-26T09:49:45Z<p></p>
<p><b>New page</b></p><div></div>Lina