http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-ImperialCollege/index.php?action=history&feed=atom&title=Answer_5.1%3A4 Answer 5.1:4 - Revision history 2026-04-08T00:54:15Z Revision history for this page on the wiki MediaWiki 1.11.1 http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-ImperialCollege/index.php?title=Answer_5.1:4&diff=6282&oldid=prev Tek: New page: {| width="100%" cellspacing="10px" |a) |width="100%" | \sin^2 x+\cos x |- |b) |width="100%" | \cos v=\cos\dfrac{3\pi}{2} |- |c) |width="100%" | \cot 2x=\dfrac{1}{\tan 2x} |- |d) |width="10... 2009-01-28T14:22:45Z <p>New page: {| width=&quot;100%&quot; cellspacing=&quot;10px&quot; |a) |width=&quot;100%&quot; | \sin^2 x+\cos x |- |b) |width=&quot;100%&quot; | \cos v=\cos\dfrac{3\pi}{2} |- |c) |width=&quot;100%&quot; | \cot 2x=\dfrac{1}{\tan 2x} |- |d) |width=&quot;10...</p> <p><b>New page</b></p><div>{| width=&quot;100%&quot; cellspacing=&quot;10px&quot;<br /> |a)<br /> |width=&quot;100%&quot; | \sin^2 x+\cos x<br /> |-<br /> |b)<br /> |width=&quot;100%&quot; | \cos v=\cos\dfrac{3\pi}{2}<br /> |-<br /> |c)<br /> |width=&quot;100%&quot; | \cot 2x=\dfrac{1}{\tan 2x}<br /> |-<br /> |d)<br /> |width=&quot;100%&quot; | \tan\dfrac{u}{2}=\dfrac{\sin u}{1+\cos u}<br /> |}</div> Tek