Answer 5.1:2 - Revision history

Tek at 14:31, 28 January 2009

2009-01-28T14:31:44Z

←Older revision		Revision as of 14:31, 28 January 2009
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	{\| width="100%" cellspacing="10px"		{\| width="100%" cellspacing="10px"
	\|a)		\|a)
-	\|width="100%" \| ~~<nowiki><math></nowiki>~~3\times 4\pm 4~~<nowiki></math></nowiki>~~	+	\|width="100%" \| 3\times 4\pm 4
	\|-		\|-
	\|b)		\|b)
-	\|width="100%" \| ~~<nowiki><math></nowiki>~~4x^2-\sqrt{x}~~<nowiki></math></nowiki>~~	+	\|width="100%" \| 4x^2-\sqrt{x}
	\|-		\|-
	\|c)		\|c)
-	\|width="100%" \| ~~<nowiki><math></nowiki>~~4\times 3^n\ge n^3~~<nowiki></math></nowiki>~~	+	\|width="100%" \| 4\times 3^n\ge n^3
	\|-		\|-
	\|d)		\|d)
-	\|width="100%" \| ~~<nowiki><math></nowiki>~~3-(5-2)=-(-3+5-2)~~<nowiki></math></nowiki>~~	+	\|width="100%" \| 3-(5-2)=-(-3+5-2)
	\|}		\|}

Tek at 14:18, 28 January 2009

2009-01-28T14:18:11Z

←Older revision		Revision as of 14:18, 28 January 2009
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	{\| width="100%" cellspacing="10px"		{\| width="100%" cellspacing="10px"
	\|a)		\|a)
-	\|width="50%" \| ~~<~~math~~>\cos{v} = \cos{\displaystyle \frac{~~3\~~pi}{2}}<~~/math~~>~~	+	\|width="100%" \| <nowiki><math></nowiki>3\times 4\pm 4<nowiki></math></nowiki>
		+	\|-
	\|b)		\|b)
-	\|width="50%" \| ~~<~~math~~>\tan\displaystyle\frac{u}{~~2}=\~~frac~~{~~\sin u~~}~~{1+\cos u}<~~/math~~>~~	+	\|width="100%" \| <nowiki><math></nowiki>4x^2-\sqrt{x}<nowiki></math></nowiki>
	\|-		\|-
	\|c)		\|c)
-	\|\| <~~br/~~>~~<~~math~~>\left\{\eqalign{ <br/~~>	+	\|width="100%" \| <nowiki><math></nowiki>4\times 3^n\ge n^3<nowiki></math></nowiki>
-	~~x&=n\pi\cr~~ <br/>	+	\|-
-	~~x&=\displaystyle \frac{\pi}{~~4}+\~~displaystyle~~ \~~frac{~~n~~\pi}{2}~~ <br/>	+
-	~~}\right.</math>~~	+
	\|d)		\|d)
-	\|\| ~~<~~math~~> \bigl(\sqrt[\scriptstyle4]~~3~~\,\bigr~~)^3~~\ \sqrt{2~~ + ~~\sqrt{4}}<~~/math~~>~~	+	\|width="100%" \| <nowiki><math></nowiki>3-(5-2)=-(-3+5-2)<nowiki></math></nowiki>
	\|}		\|}

Lina at 13:17, 22 January 2009

2009-01-22T13:17:46Z

←Older revision		Revision as of 13:17, 22 January 2009
Line 1:		Line 1:
	{\| width="100%" cellspacing="10px"		{\| width="100%" cellspacing="10px"
	\|a)		\|a)
-	\|width="50%" \| <math>\cos{v} = \cos{\displaystyle \frac{3\pi}{2}}</math>	+	\|width="50%" \| <math>\cos{v} = \cos{\displaystyle \frac{3\pi}{2}}</math>
	\|b)		\|b)
	\|width="50%" \| <math>\tan\displaystyle\frac{u}{2}=\frac{\sin u}{1+\cos u}</math>		\|width="50%" \| <math>\tan\displaystyle\frac{u}{2}=\frac{\sin u}{1+\cos u}</math>
	\|-		\|-
	\|c)		\|c)
-	\|\| <math>\left\{\eqalign{	+	\|\| <br/><math>\left\{\eqalign{ <br/>
-	x&=n\pi\cr	+	x&=n\pi\cr <br/>
-	x&=\displaystyle \frac{\pi}{4}+\displaystyle \frac{n\pi}{2}	+	x&=\displaystyle \frac{\pi}{4}+\displaystyle \frac{n\pi}{2} <br/>
	}\right.</math>		}\right.</math>
	\|d)		\|d)
	\|\| <math> \bigl(\sqrt[\scriptstyle4]3\,\bigr)^3\ \sqrt{2 + \sqrt{4}}</math>		\|\| <math> \bigl(\sqrt[\scriptstyle4]3\,\bigr)^3\ \sqrt{2 + \sqrt{4}}</math>
	\|}		\|}

Lina at 13:16, 22 January 2009

2009-01-22T13:16:18Z

←Older revision		Revision as of 13:16, 22 January 2009
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	\|-		\|-
	\|c)		\|c)
-	\|\| <math>\left\{\eqalign{ ~~<br/>~~	+	\|\| <math>\left\{\eqalign{
-	x&=n\pi\cr ~~<br/>~~	+	x&=n\pi\cr
-	x&=\displaystyle \frac{\pi}{4}+\displaystyle \frac{n\pi}{2} ~~<br/>~~	+	x&=\displaystyle \frac{\pi}{4}+\displaystyle \frac{n\pi}{2}
	}\right.</math>		}\right.</math>
	\|d)		\|d)
	\|\| <math> \bigl(\sqrt[\scriptstyle4]3\,\bigr)^3\ \sqrt{2 + \sqrt{4}}</math>		\|\| <math> \bigl(\sqrt[\scriptstyle4]3\,\bigr)^3\ \sqrt{2 + \sqrt{4}}</math>
	\|}		\|}

Lina at 13:12, 22 January 2009

2009-01-22T13:12:16Z

←Older revision		Revision as of 13:12, 22 January 2009
Line 1:		Line 1:
	{\| width="100%" cellspacing="10px"		{\| width="100%" cellspacing="10px"
	\|a)		\|a)
-	\|width="50%" \| \cos{v} = \cos{\displaystyle \frac{3\pi}{2}}	+	\|width="50%" \| <math>\cos{v} = \cos{\displaystyle \frac{3\pi}{2}}</math>
	\|b)		\|b)
-	\|width="50%" \| \tan\displaystyle\frac{u}{2}=\frac{\sin u}{1+\cos u}	+	\|width="50%" \| <math>\tan\displaystyle\frac{u}{2}=\frac{\sin u}{1+\cos u}</math>
	\|-		\|-
	\|c)		\|c)
-	\|\| \left\{\eqalign{	+	\|\| <math>\left\{\eqalign{ <br/>
-	x&=n\pi\cr	+	x&=n\pi\cr <br/>
-	x&=\displaystyle \frac{\pi}{4}+\displaystyle \frac{n\pi}{2}	+	x&=\displaystyle \frac{\pi}{4}+\displaystyle \frac{n\pi}{2} <br/>
-	}\right.	+	}\right.</math>
	\|d)		\|d)
	\|\| <math> \bigl(\sqrt[\scriptstyle4]3\,\bigr)^3\ \sqrt{2 + \sqrt{4}}</math>		\|\| <math> \bigl(\sqrt[\scriptstyle4]3\,\bigr)^3\ \sqrt{2 + \sqrt{4}}</math>
	\|}		\|}

Lina: New page: {| width="100%" cellspacing="10px" |a) |width="50%" | \cos{v} = \cos{\displaystyle \frac{3\pi}{2}} |b) |width="50%" | \tan\displaystyle\frac{u}{2}=\frac{\sin u}{1+\cos u} |- |c) || \left\{...

2009-01-22T13:11:08Z

New page: {| width="100%" cellspacing="10px" |a) |width="50%" | \cos{v} = \cos{\displaystyle \frac{3\pi}{2}} |b) |width="50%" | \tan\displaystyle\frac{u}{2}=\frac{\sin u}{1+\cos u} |- |c) || \left\{...

New page

{| width="100%" cellspacing="10px"
|a)
|width="50%" | \cos{v} = \cos{\displaystyle \frac{3\pi}{2}}
|b)
|width="50%" | \tan\displaystyle\frac{u}{2}=\frac{\sin u}{1+\cos u}
|-
|c)
|| \left\{\eqalign{
x&=n\pi\cr
x&=\displaystyle \frac{\pi}{4}+\displaystyle \frac{n\pi}{2}
}\right.
|d)
|| <math> \bigl(\sqrt[\scriptstyle4]3\,\bigr)^3\ \sqrt{2 + \sqrt{4}}</math>
|}