Oskar: Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"| $\displaystyle\frac{1}{2}\arctan\left(\frac{x}{2}\right)+C$ |b) |width="50%"| $\displaystyle\frac{1}{\sqrt3}\arctan\left(...$

Oskar — Mon, 07 Apr 2008 09:13:36 GMT

Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"|<math>\displaystyle\frac{1}{2}\arctan\left(\frac{x}{2}\right)+C</math> |b) |width="50%"| <math>\displaystyle\frac{1}{\sqrt3}\arctan\left(...

Ny sida

{| width="100%" cellspacing="10px"
|a)
|width="50%"|<math>\displaystyle\frac{1}{2}\arctan\left(\frac{x}{2}\right)+C</math>
|b)
|width="50%"| <math>\displaystyle\frac{1}{\sqrt3}\arctan\left(\frac{x-1}{\sqrt3}\right)+C</math>
|-
|c)
|width="50%"| <math>\displaystyle\frac{1}{2}\arctan\left(\frac{x+2}{2}\right)+C</math>
|d)
|width="50%"| <math>x-\arctan x + C</math>
|}

Svar 2.2:4 - Versionshistorik

Oskar: Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"|\displaystyle\frac{1}{2}\arctan\left(\frac{x}{2}\right)+C |b) |width="50%"| \displaystyle\frac{1}{\sqrt3}\arctan\left(...

Oskar: Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"| $\displaystyle\frac{1}{2}\arctan\left(\frac{x}{2}\right)+C$ |b) |width="50%"| $\displaystyle\frac{1}{\sqrt3}\arctan\left(...$