Oskar: Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%"| $\displaystyle\frac{1}{2\sqrt{x}\sqrt{x+1}}$ |b) |width="33%"| $\displaystyle - \frac{1}{(x-1)^{3/2}\sqrt{x+1}}$ |...

Oskar — Fri, 04 Apr 2008 08:14:42 GMT

Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%"| <math>\displaystyle\frac{1}{2\sqrt{x}\sqrt{x+1}}</math> |b) |width="33%"| <math>\displaystyle - \frac{1}{(x-1)^{3/2}\sqrt{x+1}}</math> |...

Ny sida

{| width="100%" cellspacing="10px"
|a)
|width="33%"| <math>\displaystyle\frac{1}{2\sqrt{x}\sqrt{x+1}}</math>
|b)
|width="33%"| <math>\displaystyle - \frac{1}{(x-1)^{3/2}\sqrt{x+1}}</math>
|c)
|width="33%"| <math>\displaystyle - \frac{1-2x^2}{x^2(1-x^2)^{3/2}}</math>
|-
|d)
|width="33%"| <math>-\cos\cos\sin x \cdot \sin\sin x \cdot \cos x</math>
|e)
|width="33%"| <math>e^{\sin x^2}\cdot \cos x^2 \cdot 2x</math>
|f)
|width="33%"| <math>\displaystyle x^{\tan x}\Bigl(\frac{\ln x}{\cos^2x}+\frac{\tan x}{x}\Bigr)</math>
|}

Svar 1.2:3 - Versionshistorik

Oskar: Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%"| \displaystyle\frac{1}{2\sqrt{x}\sqrt{x+1}} |b) |width="33%"| \displaystyle - \frac{1}{(x-1)^{3/2}\sqrt{x+1}} |...

Oskar: Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%"| $\displaystyle\frac{1}{2\sqrt{x}\sqrt{x+1}}$ |b) |width="33%"| $\displaystyle - \frac{1}{(x-1)^{3/2}\sqrt{x+1}}$ |...