http://wiki.sommarmatte.se/wikis/2008/forberedandematte2/index.php?action=history&feed=atom&title=Svar_1.2%3A1 Svar 1.2:1 - Versionshistorik 2026-04-05T20:16:39Z Versionshistorik för denna sida på wikin MediaWiki 1.11.1 http://wiki.sommarmatte.se/wikis/2008/forberedandematte2/index.php?title=Svar_1.2:1&diff=128&oldid=prev Oskar: Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%"| <math>\cos^2x-\sin^2x=\cos2x</math> |b) |width="33%"| <math>2x\ln x+ x</math> |c) |width="33%"| <math>\displaystyle\frac{x^2+2x-1}{(x+1)... 2008-04-04T07:58:06Z <p>Ny sida: {| width=&quot;100%&quot; cellspacing=&quot;10px&quot; |a) |width=&quot;33%&quot;| &lt;math&gt;\cos^2x-\sin^2x=\cos2x&lt;/math&gt; |b) |width=&quot;33%&quot;| &lt;math&gt;2x\ln x+ x&lt;/math&gt; |c) |width=&quot;33%&quot;| &lt;math&gt;\displaystyle\frac{x^2+2x-1}{(x+1)...</p> <p><b>Ny sida</b></p><div>{| width=&quot;100%&quot; cellspacing=&quot;10px&quot;<br /> |a)<br /> |width=&quot;33%&quot;| &lt;math&gt;\cos^2x-\sin^2x=\cos2x&lt;/math&gt;<br /> |b)<br /> |width=&quot;33%&quot;| &lt;math&gt;2x\ln x+ x&lt;/math&gt;<br /> |c)<br /> |width=&quot;33%&quot;| &lt;math&gt;\displaystyle\frac{x^2+2x-1}{(x+1)^2}=1-\frac{2}{(x+1)^2}&lt;/math&gt;<br /> |-<br /> |d)<br /> |width=&quot;33%&quot;| &lt;math&gt;\displaystyle\frac{\cos x}{x}-\frac{\sin x}{x^2}&lt;/math&gt;<br /> |e)<br /> |width=&quot;33%&quot;| &lt;math&gt;\displaystyle\frac{1}{\ln x}-\frac{1}{(\ln x)^2}&lt;/math&gt;<br /> |f)<br /> |width=&quot;33%&quot;| &lt;math&gt;\displaystyle \frac{\ln x + 1}{\sin x}-\frac{x\ln x \cos x}{\sin^2x}&lt;/math&gt;<br /> |}</div> Oskar