Solution 3.1:1b
From Förberedande kurs i matematik 2
When we remove the parentheses, the terms inside change sign,
| \displaystyle 3i-(2-i)=3i-2+i\,\textrm{.} |
Then, we collect together real and imaginary parts,
| \displaystyle \begin{align}
3i-2+i &=-2+(3i+i)\\[5pt] &=-2+(3+1)i\\[5pt] &=-2+4i\,\textrm{.} \end{align} |
