Answer 3.4:7

From Förberedande kurs i matematik 2

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Oskar (Talk | contribs)
(Ny sida: <math>(z-1)(z-2)(z-4) = z^3 -7z^2 + 14z - 8</math>)
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Revision as of 14:51, 7 April 2008

\displaystyle (z-1)(z-2)(z-4) = z^3 -7z^2 + 14z - 8