Answer 3.3:3
From Förberedande kurs i matematik 2
(Difference between revisions)
Oskar (Talk | contribs)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"|<math>(z+1)^2+2</math> |b) |width="50%"| <math>\left(z+\frac{3}{2}i\,\right)^2+2</math> |- |c) |width="50%"| <math>-(z-2+i)^2+4(1-i)</mat...)
Next diff →
Revision as of 12:59, 7 April 2008
| a) | \displaystyle (z+1)^2+2 | b) | \displaystyle \left(z+\frac{3}{2}i\,\right)^2+2 |
| c) | \displaystyle -(z-2+i)^2+4(1-i) | d) | \displaystyle i\bigl(z+\frac{3}{2}-i\bigl)^2-4-\frac{5}{4}\,i |
