Answer 1.3:7
From Förberedande kurs i matematik 2
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(Ny sida: Vinkeln <math>2\pi\bigl(1-\sqrt{\frac{2}{3}}\,\bigr)\,</math> radianer ska tas bort.)
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Revision as of 10:07, 4 April 2008
Vinkeln \displaystyle 2\pi\bigl(1-\sqrt{\frac{2}{3}}\,\bigr)\, radianer ska tas bort.
