Answer 3.3:4

From Förberedande kurs i matematik 2

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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"|<math>z= \left\{\begin{matrix} \phantom{-}(1+i)/\sqrt{2}\\ -(1+i)/\sqrt{2}\\ \end{matrix}\right.</math> |b) |width="50%"| <math>z = \left...)
Current revision (14:08, 16 September 2008) (edit) (undo)
m (Svar 3.3:4 moved to Answer 3.3:4: Robot: moved page)
 

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a) \displaystyle z= \left\{\begin{matrix} \phantom{-}(1+i)/\sqrt{2}\\ -(1+i)/\sqrt{2}\\ \end{matrix}\right. b) \displaystyle z = \left\{\begin{matrix} 2+i \\ 2-i \\ \end{matrix}\right.
c) \displaystyle z= \left\{\begin{matrix} -1 \\ \phantom{-}3 \\ \end{matrix}\right. d) \displaystyle z= \left\{\begin{matrix} (1+i\sqrt{15})/4\\ (1-i\sqrt{15})/4 \end{matrix}\right.