Answer 3.3:3

From Förberedande kurs i matematik 2

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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"|<math>(z+1)^2+2</math> |b) |width="50%"| <math>\left(z+\frac{3}{2}i\,\right)^2+2</math> |- |c) |width="50%"| <math>-(z-2+i)^2+4(1-i)</mat...)
Current revision (14:08, 16 September 2008) (edit) (undo)
m (Svar 3.3:3 moved to Answer 3.3:3: Robot: moved page)
 

Current revision

a) \displaystyle (z+1)^2+2 b) \displaystyle \left(z+\frac{3}{2}i\,\right)^2+2
c) \displaystyle -(z-2+i)^2+4(1-i) d) \displaystyle i\bigl(z+\frac{3}{2}-i\bigl)^2-4-\frac{5}{4}\,i