Solution 3.1:1b

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Current revision (14:47, 29 October 2008) (edit) (undo)
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{{NAVCONTENT_START}}
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When we remove the parentheses, the terms inside change sign,
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When we remove the parentheses, the terms inside change sign:
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<math>3i-(2-i)=3i-2+i.</math>
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{{Displayed math||<math>3i-(2-i)=3i-2+i\,\textrm{.}</math>}}
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Then, we collect together real and imaginary parts:
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Then, we collect together real and imaginary parts,
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<math>\begin{align}3i-2+i&=-2+(3i+i)\\
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{{Displayed math||<math>\begin{align}
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&=-2+(3+1)i\\
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3i-2+i
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&=-2+4i\end{align}</math>
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&=-2+(3i+i)\\[5pt]
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{{NAVCONTENT_STOP}}
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&=-2+(3+1)i\\[5pt]
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&=-2+4i\,\textrm{.}
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\end{align}</math>}}

Current revision

When we remove the parentheses, the terms inside change sign,

\displaystyle 3i-(2-i)=3i-2+i\,\textrm{.}

Then, we collect together real and imaginary parts,

\displaystyle \begin{align}

3i-2+i &=-2+(3i+i)\\[5pt] &=-2+(3+1)i\\[5pt] &=-2+4i\,\textrm{.} \end{align}

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