Answer 3.4:7
From Förberedande kurs i matematik 2
(Difference between revisions)
(Ny sida: <math>(z-1)(z-2)(z-4) = z^3 -7z^2 + 14z - 8</math>) |
m (Svar 3.4:7 moved to Answer 3.4:7: Robot: moved page) |
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| - | <math>(z-1)(z-2)(z-4) = z^3 -7z^2 + 14z - 8</math> | + | {| width="100%" cellspacing="10px" |
| + | |a) | ||
| + | |width="50%"| <math>(z-1)(z-2)(z-4) = z^3 -7z^2 + 14z - 8</math> | ||
| + | |b) | ||
| + | |width="50%"| <math>(z+1-i)(z+1+i) = z^2+2z+2</math> | ||
| + | |} | ||
Current revision
| a) | \displaystyle (z-1)(z-2)(z-4) = z^3 -7z^2 + 14z - 8 | b) | \displaystyle (z+1-i)(z+1+i) = z^2+2z+2 |
