Solution 1.2:1b

From Förberedande kurs i matematik 2

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We use the product rule with <math>x^2</math> and <math>\ln x</math> as factors,
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{{Displayed math||<math>\begin{align}
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\bigl(x^{2}\ln x\bigr)'
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&= \bigl(x^2\bigr)'\,\ln x + x^2\,(\ln x)'\\[5pt]
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&= 2x\cdot\ln x + x^2\cdot\frac{1}{x}\\[5pt]
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&= 2x\ln x + x\,\textrm{.}
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\end{align}</math>}}

Current revision

We use the product rule with \displaystyle x^2 and \displaystyle \ln x as factors,

\displaystyle \begin{align}

\bigl(x^{2}\ln x\bigr)' &= \bigl(x^2\bigr)'\,\ln x + x^2\,(\ln x)'\\[5pt] &= 2x\cdot\ln x + x^2\cdot\frac{1}{x}\\[5pt] &= 2x\ln x + x\,\textrm{.} \end{align}