Solution 3.1:1c
From Förberedande kurs i matematik 2
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- | {{ | + | Complex numbers satisfy the same rules of arithmetic as ordinary numbers, with the addition that <math>i^2=-1</math>. The distributivity rule gives that |
- | < | + | |
- | {{ | + | {{Displayed math||<math>\begin{align} |
+ | i(2+3i) | ||
+ | &= i\cdot 2 + i\cdot 3i\\[5pt] | ||
+ | &= 2i+3i^2\\[5pt] | ||
+ | &= 2i+3\cdot (-1)\\[5pt] | ||
+ | &= 2i-3\\[5pt] | ||
+ | &= -3+2i\,\textrm{.} | ||
+ | \end{align}</math>}} |
Current revision
Complex numbers satisfy the same rules of arithmetic as ordinary numbers, with the addition that \displaystyle i^2=-1. The distributivity rule gives that
\displaystyle \begin{align}
i(2+3i) &= i\cdot 2 + i\cdot 3i\\[5pt] &= 2i+3i^2\\[5pt] &= 2i+3\cdot (-1)\\[5pt] &= 2i-3\\[5pt] &= -3+2i\,\textrm{.} \end{align} |