Answer 2.1:4

From Förberedande kurs i matematik 2

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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="100%"| <math>3-\displaystyle\frac{1}{\sqrt2}</math> a.e. |- |b) |width="100%"| <math>\displaystyle 4.\sqrt{3}</math> a.e. |- |c) |width="100%"...)
Current revision (14:01, 16 September 2008) (edit) (undo)
m (Svar 2.1:4 moved to Answer 2.1:4: Robot: moved page)
 
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{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|a)
|a)
-
|width="100%"| <math>3-\displaystyle\frac{1}{\sqrt2}</math> a.e.
+
|width="100%"| <math>3-\displaystyle\frac{1}{\sqrt2}</math> u.a.
|-
|-
|b)
|b)
-
|width="100%"| <math>\displaystyle 4.\sqrt{3}</math> a.e.
+
|width="100%"| <math>\displaystyle 4.\sqrt{3}</math> u.a.
|-
|-
|c)
|c)
-
|width="100%"| <math>32</math> a.e.
+
|width="100%"| <math>32</math> u.a.
|-
|-
|d)
|d)
-
|width="100%"| <math>\sqrt{2}-1-\ln(\sqrt{2}-1)\,</math> a.e.
+
|width="100%"| <math>\sqrt{2}-1-\ln(\sqrt{2}-1)\,</math> u.a.
|-
|-
|e)
|e)
-
|width="100%"| <math>\displaystyle\frac{9}{2}</math> a.e.
+
|width="100%"| <math>\displaystyle\frac{9}{2}</math> u.a.
|}
|}

Current revision

a) \displaystyle 3-\displaystyle\frac{1}{\sqrt2} u.a.
b) \displaystyle \displaystyle 4.\sqrt{3} u.a.
c) \displaystyle 32 u.a.
d) \displaystyle \sqrt{2}-1-\ln(\sqrt{2}-1)\, u.a.
e) \displaystyle \displaystyle\frac{9}{2} u.a.