Svar 2.1:7
Aus Förberedande kurs i matematik 1
(Unterschied zwischen Versionen)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%" | <math>\displaystyle \frac{4}{(x+3)(x+5)}</math> |b) |width="33%" | <math>\displaystyle \frac{x^4-x^3+x^2+x-1}{x^2(x-1)}</math> |c) |wi...) |
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%" | <math>\displaystyle \frac{4}{(x+3)(x+5)}</math> |b) |width="33%" | <math>\displaystyle \frac{x^4-x^3+x^2+x-1}{x^2(x-1)}</math> |c) |wi...) |
Aktuelle Version
| a) | \displaystyle \displaystyle \frac{4}{(x+3)(x+5)} | b) | \displaystyle \displaystyle \frac{x^4-x^3+x^2+x-1}{x^2(x-1)} | c) | \displaystyle \displaystyle \frac{ax(a+1-x)}{(a+1)^2} |
