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Solution 4.3:4c

Revision as of 14:12, 9 October 2008 by Tek (Talk | contribs)

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The formula for double angles gives

\displaystyle \sin 2v=2\sin v\cos v

and from exercise b, we have \displaystyle \sin v = \sqrt{1-b^2}\,. Thus,

\displaystyle \sin 2v = 2b\sqrt{1-b^2}\,\textrm{.}