Solution 4.4:8b

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Suppose that \displaystyle \text{cos }x\ne 0 , so that we can divide both sides by \displaystyle \text{cos }x to obtain


\displaystyle \frac{\sin x}{\cos x}=\sqrt{3} i.e. \displaystyle \tan x=\sqrt{3}


This equation has the solutions \displaystyle x=\frac{\pi }{3}+n\pi for all integers \displaystyle n.

If, on the other hand, \displaystyle \text{cos }x=0, so \displaystyle \text{sin }x\text{ }=\pm \text{1} ( draw a unit circle) and the equation cannot have such a solution.

Thus, the equation has the solutions


\displaystyle x=\frac{\pi }{3}+n\pi ( \displaystyle n an arbitrary integer).