Solution 4.2:8

From Förberedande kurs i matematik 1

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We start by drawing three auxiliary triangles, and calling the three vertical sides \displaystyle x,\ y and \displaystyle z, as shown in the figure.


Using the definition of cosine, we can work out \displaystyle x\text{ } and \displaystyle y from


\displaystyle x=a\cos \alpha


\displaystyle y=b\cos \beta

and, for the same reason, we know that \displaystyle z\text{ } satisfies the relation


\displaystyle z=l\cos \gamma


In addition, we know that the lengths \displaystyle x,\ y and \displaystyle z satisfy the equality


\displaystyle z=x-y


If we substitute in the expressions for \displaystyle x,\ y and \displaystyle z, we obtain the trigonometric equation


\displaystyle l\cos \gamma =a\cos \alpha -b\cos \beta


where \displaystyle \gamma is the only unknown.