Solution 4.2:5c

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If we express the angle \displaystyle \text{33}0^{\circ } in radians, we obtain


\displaystyle \text{33}0^{\circ }=\text{33}0^{\circ }\centerdot \frac{\pi }{180^{\circ }} radians \displaystyle =\frac{11\pi }{6} radians

and from exercise 3.3:1g, we know that


\displaystyle \cos 330^{\circ }=\cos \frac{11\pi }{6}=\frac{\sqrt{3}}{2}.