Solution 2.2:5e
From Förberedande kurs i matematik 1
The line should go through the points \displaystyle \left( 5 \right.,\left. 0 \right) and \displaystyle \left( 0 \right.,\left. -8 \right) which must therefore satisfy the equation of the line \displaystyle y=kx+m, i.e.
\displaystyle 0=k\centerdot 5+m
From the other equation, we get
\displaystyle m=-8
and substituting this into the first equation gives
\displaystyle 0=5k-8\ \Leftrightarrow \ k={8}/{5}\;
The gradient of the line is
\displaystyle {8}/{5}\;.
