Solution 2.1:7a

From Förberedande kurs i matematik 1

Revision as of 12:38, 16 September 2008 by Ian (Talk | contribs)
Jump to: navigation, search

If we multiply the top and bottom of the first fraction by \displaystyle x+5 and the second by \displaystyle x+3, then they will both have the same numerator and we can work out the expression by subtracting the numerators:


\displaystyle \begin{align} & \frac{2}{x+3}-\frac{2}{x+5}=\frac{2}{x+3}\centerdot \frac{x+5}{x+5}-\frac{2}{x+5}\centerdot \frac{x+3}{x+3} \\ & =\frac{2\left( x+5 \right)-2\left( x+3 \right)}{\left( x+3 \right)\left( x+5 \right)}=\frac{2x+10-2x-6}{\left( x+3 \right)\left( x+5 \right)}=\frac{4}{\left( x+3 \right)\left( x+5 \right)} \\ \end{align}