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Answer 2.1:7

Revision as of 12:07, 31 March 2008 by Lina (Talk | contribs)

\displaystyle \displaystyle \frac{4}{(x+3)(x+5)}

\displaystyle \displaystyle \frac{x^4-x^3+x^2+x-1}{x^2(x-1)}

\displaystyle \displaystyle \frac{ax(a+1-x)}{(a+1)^2}