Solution 2.3:1b

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When we complete the square, it is only the first two terms, \displaystyle x^{2}+2x , that are involved. The general formula for completing the square states that \displaystyle x^{2}+ax equals


\displaystyle \left( x+\frac{a}{2} \right)^{2}-\left( \frac{a}{2} \right)^{2}


Note how the coefficient \displaystyle a in front of the \displaystyle x turns up halved in two places.

If we use this formula, we obtain


\displaystyle x^{2}+2x=\left( x+\frac{2}{2} \right)^{2}-\left( \frac{2}{2} \right)^{2}=\left( x+1 \right)^{2}-1


and if we subtract the last " \displaystyle 1 " , we obtain


\displaystyle x^{2}+2x-1=\left( x+1 \right)^{2}-1-1=\left( x+1 \right)^{2}-2


To be completely certain that we have used the correct formula, we can expand the quadratic on the right-hand side,


\displaystyle \left( x+1 \right)^{2}-2=x^{2}+2x+1-2=x^{2}+2x-1


and see that the relation really holds.