Answer 3.1:8
From Förberedande kurs i matematik 1
(Difference between revisions)
Oskar (Talk | contribs)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%" | <math>\sqrt[\scriptstyle3]6 > \sqrt[\scriptstyle3]5</math> |b) |width="50%" | <math>7 > \sqrt7</math> |- |c) |width="50%" | <math>\sqr...)
Next diff →
Revision as of 13:08, 1 April 2008
| a) | \displaystyle \sqrt[\scriptstyle3]6 > \sqrt[\scriptstyle3]5 | b) | \displaystyle 7 > \sqrt7 |
| c) | \displaystyle \sqrt7 > 2{,}5 | d) | \displaystyle \sqrt[\scriptstyle3]2\cdot3 > \sqrt2\bigl(\sqrt[\scriptstyle4]3\,\bigr)^3 |
