Answer 2.3:5

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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="100%" | Exempelvis <math>\ x^2+14x+49=0\,</math> |- |b) |width="100" | <math>3< x<4</math> |- |c) |width="100" | <math>b=-5</math> |})
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Revision as of 11:30, 1 April 2008

a) Exempelvis \displaystyle \ x^2+14x+49=0\,
b) \displaystyle 3< x<4
c) \displaystyle b=-5
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