Answer 2.1:6
From Förberedande kurs i matematik 1
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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%" | <math>2y</math> |b) |width="50%" | <math>\displaystyle\frac{-x+12}{(x-2)(x+3)}</math> |- |c) |width="50%" | <math>\displaystyle\frac{b...)
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Revision as of 12:05, 31 March 2008
| a) | \displaystyle 2y | b) | \displaystyle \displaystyle\frac{-x+12}{(x-2)(x+3)} |
| c) | \displaystyle \displaystyle\frac{b}{a(a-b)} | d) | \displaystyle \displaystyle\frac{a(a+b)}{4b} |
