From Förberedande kurs i matematik 1

Revision as of 11:17, 28 September 2008 (edit) Ian (Talk | contribs) ← Previous diff		Current revision (14:22, 8 October 2008) (edit) (undo) Tek (Talk | contribs) m
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		+	The side adjacent to the angle of 50° is marked ''x'' and the opposite is the side of length 19.
		+
	[[Image:4_2_1_f.gif|center]]		[[Image:4_2_1_f.gif|center]]
-	The side adjacent to the angle of	+	If we write the tangent for the angle, this gives a relation which contains ''x'' as the only unknown,
-	<math>\text{5}0^{\circ }</math>	+
-	is marked	+
-	<math>x</math>	+
-	and the opposite is the side of length	+
-	<math>\text{19}</math>.	+
-		+
-		+
-		+
-	If we write the tangent for the angle, this gives a relation which contains	+
-	<math>x</math>	+
-	as the only unknown,	+
-		+
-		+
-	<math>\tan 50^{\circ }=\frac{19}{x}</math>	+
		+	{{Displayed math||<math>\tan 50^{\circ} = \frac{19}{x}\,\textrm{.}</math>}}
	This gives		This gives
-		+	{{Displayed math||<math>x=\frac{19}{\tan 50^{\circ }}\quad ({}\approx 15\textrm{.}9)\,\textrm{.}</math>}}
-	<math>x=\frac{19}{\tan 50^{\circ }}\quad \left( \approx 15.9 \right)</math>	+

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Current revision

The side adjacent to the angle of 50° is marked x and the opposite is the side of length 19.

If we write the tangent for the angle, this gives a relation which contains x as the only unknown,

\displaystyle \tan 50^{\circ} = \frac{19}{x}\,\textrm{.}

This gives

\displaystyle x=\frac{19}{\tan 50^{\circ }}\quad ({}\approx 15\textrm{.}9)\,\textrm{.}