Solution 4.2:1d

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The side marked ''x'' is the hypotenuse in the right-angled triangle and the side of length 16 is the adjacent to the angle of 20°.
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[[Image:4_2_1_d.gif|center]]
[[Image:4_2_1_d.gif|center]]
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The side marked
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By writing the quotient for <math>\cos 20^{\circ}</math>, we obtain the relation
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<math>x</math>
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is the hypotenuse in the right-angled triangle and the side of length
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<math>\text{16}</math>
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is the adjacent to the angle of
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<math>\text{2}0^{\circ }</math>.
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By writing the quotient for
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<math>\text{cos20}^{\circ }</math>, we obtain the relation
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<math>\text{cos20}^{\circ }=\frac{16}{x}</math>
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{{Displayed math||<math>\cos 20^{\circ} = \frac{16}{x}</math>}}
and this gives
and this gives
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{{Displayed math||<math>x = \frac{16}{\cos20^{\circ}}\quad ({}\approx 17\textrm{.}0)\,\textrm{.}</math>}}
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<math>x=\frac{16}{\text{cos20}^{\circ }}\quad \left( \approx 17.0 \right).</math>
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Current revision

The side marked x is the hypotenuse in the right-angled triangle and the side of length 16 is the adjacent to the angle of 20°.

By writing the quotient for \displaystyle \cos 20^{\circ}, we obtain the relation

\displaystyle \cos 20^{\circ} = \frac{16}{x}

and this gives

\displaystyle x = \frac{16}{\cos20^{\circ}}\quad ({}\approx 17\textrm{.}0)\,\textrm{.}
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