From Förberedande kurs i matematik 1

Revision as of 10:27, 28 September 2008 (edit) Ian (Talk | contribs) ← Previous diff		Current revision (13:52, 8 October 2008) (edit) (undo) Tek (Talk | contribs) m
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	The definition of the tangent states that		The definition of the tangent states that
-		+	{| width="100%"
-		+	| width="50%" align="center"|<math>\tan u=\frac{\text{opposite}}{\text{adjacent}}</math>
-	<math>\tan u=\frac{\text{opposite}}{\text{adjacent}}</math>	+	| width="50%" align="center"|[[Image:4_2_1_a.gif]]
-		+	|}
	In our case, this means that		In our case, this means that
		+	{{Displayed math||<math>\tan 27^{\circ} = \frac{x}{13}</math>}}
-	<math>\tan 27^{\circ }=\frac{x}{13}</math>	+	which gives <math>x = 13\cdot \tan 27^{\circ}\,</math>.
-		+
-		+
-	which gives	+
-	<math>x=\text{13}\centerdot \text{tan 27}^{\circ }</math>.	+
-	NOTE: Using a calculator, we can work out what
-	<math>x\text{ }</math>
-	should be:
		+	Note: Using a calculator, we can work out what ''x'' should be,
-	<math>x=\text{13}\centerdot \text{tan 27}^{\circ }\approx 6.62</math>	+	{{Displayed math||<math>x = 13\cdot\tan 27^{\circ} \approx 6\textrm{.}62\,\textrm{.}</math>}}

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Current revision

The definition of the tangent states that

\displaystyle \tan u=\frac{\text{opposite}}{\text{adjacent}}

In our case, this means that

\displaystyle \tan 27^{\circ} = \frac{x}{13}

which gives \displaystyle x = 13\cdot \tan 27^{\circ}\,.

Note: Using a calculator, we can work out what x should be,

\displaystyle x = 13\cdot\tan 27^{\circ} \approx 6\textrm{.}62\,\textrm{.}