Solution 4.1:6b

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A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at
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A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at (''a'',''b'') and radius ''r'',
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<math>\left( a \right.,\left. b \right)</math>
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and radius
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<math>r</math>,
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<math>\left( x-a \right)^{2}+\left( y-b \right)^{2}=r^{2}</math>
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{{Displayed math||<math>(x-a)^2 + (y-b)^2 = r^2\,\textrm{.}</math>}}
In our case, we can write the equation as
In our case, we can write the equation as
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{{Displayed math||<math>(x-1)^2 + (y-2)^2 = (\sqrt{3})^2</math>}}
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<math>\left( x-1 \right)^{2}+\left( y-2 \right)^{2}=\left( \sqrt{3} \right)^{2}</math>
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and then we see that it describes a circle with centre at (1,2) and radius <math>\sqrt{3}\,</math>.
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and then we see that it describes a circle with centre at
 
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<math>\left( 1 \right.,\left. 2 \right)</math>
 
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and radius
 
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{{NAVCONTENT_START}}
 
[[Image:4_1_6_b.gif|center]]
[[Image:4_1_6_b.gif|center]]
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{{NAVCONTENT_STOP}}
 

Current revision

A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at (a,b) and radius r,

\displaystyle (x-a)^2 + (y-b)^2 = r^2\,\textrm{.}

In our case, we can write the equation as

\displaystyle (x-1)^2 + (y-2)^2 = (\sqrt{3})^2

and then we see that it describes a circle with centre at (1,2) and radius \displaystyle \sqrt{3}\,.


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