From Förberedande kurs i matematik 1

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-	{{NAVCONTENT_START}}	+	A circle is defined as all the points which have a fixed distance to the circle's midpoint. Hence, a point (''x'',''y'') lies on our circle if and only if its distance to the point (1,3) is exactly 2. Using the distance formula, we can express this condition as
-	[[Image:4_1_5_a.gif|center]]	+
-	{{NAVCONTENT_STOP}}	+	{{Displayed math||<math>\sqrt{(x-1)^2 + (y-2)^2} = 2\,\textrm{.}</math>}}
		+	After squaring, we obtain the equation of the circle in standard form,
-	A circle is defined as all the points which have a fixed distance to the circle's midpoint. Hence, a point	+	{{Displayed math||<math>(x-1)^2 + (y-2)^2 = 4\,\textrm{.}</math>}}
-	<math>\left( x \right.,\left. y \right)</math>	+
-	lies on our circle if and only if its distance to the point	+
-	<math>\left( 1 \right.,\left. 3 \right)</math>	+
-	is exactly	+
-	<math>2</math>. Using the distance formula, we can express this condition as	+
-	<math>\sqrt{\left( x-1 \right)^{2}+\left( y-2 \right)^{2}}=2</math>	+	[[Image:4_1_5_a.gif|center]]
-		+
-		+
-	After squaring, we obtain the equation of the circle in standard form:	+
-		+
-		+
-	<math>\left( x-1 \right)^{2}+\left( y-2 \right)^{2}=4</math>	+

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Current revision

A circle is defined as all the points which have a fixed distance to the circle's midpoint. Hence, a point (x,y) lies on our circle if and only if its distance to the point (1,3) is exactly 2. Using the distance formula, we can express this condition as

\displaystyle \sqrt{(x-1)^2 + (y-2)^2} = 2\,\textrm{.}

After squaring, we obtain the equation of the circle in standard form,

\displaystyle (x-1)^2 + (y-2)^2 = 4\,\textrm{.}