Answer 2.1:3
From Förberedande kurs i matematik 1
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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%" | <(x+6)(x-6)</math> |b) |width="33%" | <math>5(x+2)(x-2)</math> |c) |width="33%" | <math>$(x+3)^2</math> |- |d) || <math>(x-5)^2</math>...)
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Revision as of 11:35, 31 March 2008
| a) | <(x+6)(x-6)</math> | b) | \displaystyle 5(x+2)(x-2) | c) | \displaystyle $(x+3)^2 |
| d) | \displaystyle (x-5)^2 | e) | \displaystyle -2x(x+3)(x-3) | f) | \displaystyle (4x+1)^2 |
