Solution 3.1:8c
From Förberedande kurs i matematik 1
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| - | Since | + | Since <math>2\textrm{.}5^{2} = 2\textrm{.}5\cdot 2\textrm{.}5 = 6\textrm{.}25\,</math>, then <math>2\textrm{.}5 = \sqrt{6\textrm{.}25}\,</math>, and then we see that <math>\sqrt{7}</math> is greater than 2.5 since <math>7^{1/2} > 6\textrm{.}25^{1/2}\,</math>. |
| - | <math>2.5^{2}=2.5\ | + | |
| - | <math>2.5=\sqrt{6.25}</math>, and then we see that | + | |
| - | <math>\sqrt{7}</math> | + | |
| - | is greater than 2.5 since | + | |
| - | <math>7^ | + | |
Current revision
Since \displaystyle 2\textrm{.}5^{2} = 2\textrm{.}5\cdot 2\textrm{.}5 = 6\textrm{.}25\,, then \displaystyle 2\textrm{.}5 = \sqrt{6\textrm{.}25}\,, and then we see that \displaystyle \sqrt{7} is greater than 2.5 since \displaystyle 7^{1/2} > 6\textrm{.}25^{1/2}\,.
