From Förberedande kurs i matematik 1

Revision as of 09:28, 9 September 2008 (edit) Tekbot (Talk | contribs) m (Lösning 3.3:5f moved to Solution 3.3:5f: Robot: moved page) ← Previous diff		Revision as of 08:48, 26 September 2008 (edit) (undo) Ian (Talk | contribs) Next diff →
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-	{{NAVCONTENT_START}}	+	Since
-	<center> [[Image:3_3_5f.gif]] </center>	+	<math>\ln e=1</math>, the whole expression becomes
-	{{NAVCONTENT_STOP}}	+
		+
		+	<math>\left( e^{\ln e} \right)^{2}=\left( e^{1} \right)^{2}=e^{1\centerdot 2}=e^{2}</math>

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Revision as of 08:48, 26 September 2008

Since \displaystyle \ln e=1, the whole expression becomes

\displaystyle \left( e^{\ln e} \right)^{2}=\left( e^{1} \right)^{2}=e^{1\centerdot 2}=e^{2}