Solution 3.3:4a
From Förberedande kurs i matematik 1
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- | {{ | + | Individually, the terms are difficult to calculate, but the two logarithms can be lumped together using the logarithm law, |
- | + | <math>\text{log }a-\text{ log }b=\text{log}\left( \frac{a}{b} \right)</math>, | |
- | {{ | + | |
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+ | <math>\lg 50-\lg 5=\lg \frac{50}{5}=\lg 10=1.</math> |
Revision as of 14:46, 25 September 2008
Individually, the terms are difficult to calculate, but the two logarithms can be lumped together using the logarithm law, \displaystyle \text{log }a-\text{ log }b=\text{log}\left( \frac{a}{b} \right),
\displaystyle \lg 50-\lg 5=\lg \frac{50}{5}=\lg 10=1.