Solution 3.3:2h
From Förberedande kurs i matematik 1
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- | {{ | + | The argument in the logarithm can be rewritten as |
- | < | + | <math>\frac{1}{10^{2}}=10^{-2}</math> |
- | {{ | + | and then the log law |
+ | <math>\lg a^{b}=b\lg a</math> | ||
+ | gives the rest: | ||
+ | |||
+ | |||
+ | <math>\lg \frac{1}{10^{2}}=\lg 10^{-2}=\left( -2 \right)\centerdot \lg 10=\left( -2 \right)\centerdot 1=-2</math> |
Revision as of 13:46, 25 September 2008
The argument in the logarithm can be rewritten as \displaystyle \frac{1}{10^{2}}=10^{-2} and then the log law \displaystyle \lg a^{b}=b\lg a gives the rest:
\displaystyle \lg \frac{1}{10^{2}}=\lg 10^{-2}=\left( -2 \right)\centerdot \lg 10=\left( -2 \right)\centerdot 1=-2