Solution 2.2:4b
From Förberedande kurs i matematik 1
(Difference between revisions)
m |
|||
Line 1: | Line 1: | ||
- | By taking | + | By taking <math>4y</math> out of the relation <math>3x+4y-5=0</math>, we get |
- | <math>4y</math> | + | |
- | out of the relation | + | |
- | <math>3x+4y-5=0</math>, we get | + | |
+ | {{Displayed math||<math>4y=-3x+5\,\textrm{.}</math>}} | ||
- | + | Dividing by 4 then gives the answer in the desired form | |
- | + | {{Displayed math||<math>y=-\frac{3}{4}x+\frac{5}{4}\,\textrm{.}</math>}} | |
- | + | ||
- | + | ||
- | + | ||
- | + | ||
- | + | ||
- | <math>y=-\frac{3}{4}x+\frac{5}{4}</math> | + |
Current revision
By taking \displaystyle 4y out of the relation \displaystyle 3x+4y-5=0, we get
\displaystyle 4y=-3x+5\,\textrm{.} |
Dividing by 4 then gives the answer in the desired form
\displaystyle y=-\frac{3}{4}x+\frac{5}{4}\,\textrm{.} |