Solution 1.3:3d

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
m (Lösning 1.3:3d moved to Solution 1.3:3d: Robot: moved page)
Line 1: Line 1:
-
{{NAVCONTENT_START}}
+
Because
-
<center> [[Image:1_3_3d.gif]] </center>
+
<math>27=3\centerdot 9=3\centerdot 3\centerdot 3=3^{3}</math>
-
{{NAVCONTENT_STOP}}
+
thus,
 +
 
 +
 
 +
<math>\frac{1}{27}=\frac{1}{3^{3}}=3^{-3}</math>

Revision as of 11:40, 15 September 2008

Because \displaystyle 27=3\centerdot 9=3\centerdot 3\centerdot 3=3^{3} thus,


\displaystyle \frac{1}{27}=\frac{1}{3^{3}}=3^{-3}

Retrieved from "http://wiki.sommarmatte.se/wikis/2008/bridgecourse1-ImperialCollege/index.php/Solution_1.3:3d"