Answer 4.1:8

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
(Translated into English)
Line 1: Line 1:
{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|
|
-
|width="100%" | <math>\displaystyle \frac{10}{\pi}\textrm{ varv }\approx 3,2 \textrm{ varv} </math>
+
|width="100%" | <math>\displaystyle \frac{10}{\pi}\textrm{ revolutions }\approx 3,2 \textrm{ revolutions} </math>
|}
|}

Revision as of 10:51, 8 September 2008

\displaystyle \displaystyle \frac{10}{\pi}\textrm{ revolutions }\approx 3,2 \textrm{ revolutions}
Retrieved from "http://wiki.sommarmatte.se/wikis/2008/bridgecourse1-ImperialCollege/index.php/Answer_4.1:8"