Solution 2.1:3a
From Förberedande kurs i matematik 1
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| - | <center> [[Bild:2_1_3a.gif]] </center> | + | <!--center> [[Bild:2_1_3a.gif]] </center--> |
| + | If we look at the expression, we see that it can be written as <math>x^2-6^2</math> and can therefore be factorized using the conjugate rule. | ||
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| + | :<math> x^2-36=x^2-6^2=(x+6)(x-6).</math> | ||
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| + | Because the factors <math> x+6 </math> and <math> x-6 </math> are linear expressions, they cannot be factorized any further (as polynomial factors). | ||
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Revision as of 13:01, 13 August 2008
If we look at the expression, we see that it can be written as \displaystyle x^2-6^2 and can therefore be factorized using the conjugate rule.
- \displaystyle x^2-36=x^2-6^2=(x+6)(x-6).
Because the factors \displaystyle x+6 and \displaystyle x-6 are linear expressions, they cannot be factorized any further (as polynomial factors).
