Answer 3.4:1
From Förberedande kurs i matematik 1
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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%" | <math>x=\ln 13</math> |b) |width="33%" | <math>x=\displaystyle\frac{\ln 2 - \ln 13}{1+\ln 3}</math> |c) |width="33%" | <math>x=\displa...)
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Revision as of 10:11, 2 April 2008
| a) | \displaystyle x=\ln 13 | b) | \displaystyle x=\displaystyle\frac{\ln 2 - \ln 13}{1+\ln 3} | c) | \displaystyle x=\displaystyle\frac{\ln 7 - \ln 3}{1-\ln 2} |
