Solution 4.1:6b

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A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at
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<math>\left( a \right.,\left. b \right)</math>
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and radius
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<math>r</math>,
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<math>\left( x-a \right)^{2}+\left( y-b \right)^{2}=r^{2}</math>
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In our case, we can write the equation as
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<math>\left( x-1 \right)^{2}+\left( y-2 \right)^{2}=\left( \sqrt{3} \right)^{2}</math>
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and then we see that it describes a circle with centre at
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<math>\left( 1 \right.,\left. 2 \right)</math>
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and radius
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[[Image:4_1_6_b.gif|center]]
[[Image:4_1_6_b.gif|center]]
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<center> [[Image:4_1_6b.gif]] </center>
 
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Revision as of 11:33, 27 September 2008

A quick way to interpret the equation is to compare it with the standard formula for the equation of a circle with centre at \displaystyle \left( a \right.,\left. b \right) and radius \displaystyle r,


\displaystyle \left( x-a \right)^{2}+\left( y-b \right)^{2}=r^{2}


In our case, we can write the equation as


\displaystyle \left( x-1 \right)^{2}+\left( y-2 \right)^{2}=\left( \sqrt{3} \right)^{2}


and then we see that it describes a circle with centre at \displaystyle \left( 1 \right.,\left. 2 \right) and radius