Solution 3.3:5f
From Förberedande kurs i matematik 1
(Difference between revisions)
m (Lösning 3.3:5f moved to Solution 3.3:5f: Robot: moved page) |
|||
Line 1: | Line 1: | ||
- | + | Since | |
- | < | + | <math>\ln e=1</math>, the whole expression becomes |
- | {{ | + | |
+ | |||
+ | <math>\left( e^{\ln e} \right)^{2}=\left( e^{1} \right)^{2}=e^{1\centerdot 2}=e^{2}</math> |
Revision as of 08:48, 26 September 2008
Since \displaystyle \ln e=1, the whole expression becomes
\displaystyle \left( e^{\ln e} \right)^{2}=\left( e^{1} \right)^{2}=e^{1\centerdot 2}=e^{2}