Solution 2.1:3d

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
m (Lösning 2.1:3d moved to Solution 2.1:3d: Robot: moved page)
Current revision (08:33, 23 September 2008) (edit) (undo)
m
 
Line 1: Line 1:
-
{{NAVCONTENT_START}}
 
By writing the expression as <math> x^2 -2\cdot 5x +5^5 </math>, applying the squaring rule <math> x^2-2ax +a^2=(x-a)^2 </math> then gives
By writing the expression as <math> x^2 -2\cdot 5x +5^5 </math>, applying the squaring rule <math> x^2-2ax +a^2=(x-a)^2 </math> then gives
-
<math> \qquad
+
{{Displayed math||<math>x^2 -10x + 25 = x^2 -2\cdot 5x +5^5 = (x-5)^2\,\textrm{.}</math>}}
-
x^2 -10x +5^5 =x^2 -2\cdot 5x +5^5 =(x-5)^2
+
-
</math>
+
-
<!--<center> [[Image:2_1_3d.gif]] </center>-->
+
-
{{NAVCONTENT_STOP}}
+

Current revision

By writing the expression as \displaystyle x^2 -2\cdot 5x +5^5 , applying the squaring rule \displaystyle x^2-2ax +a^2=(x-a)^2 then gives

\displaystyle x^2 -10x + 25 = x^2 -2\cdot 5x +5^5 = (x-5)^2\,\textrm{.}