Solution 2.1:3b
From Förberedande kurs i matematik 1
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If we take out the factor 5, we see that the expression can be factorized using the conjugate rule | If we take out the factor 5, we see that the expression can be factorized using the conjugate rule | ||
- | <math> | + | {{Displayed math||<math>\begin{align} |
5x^2-20&=5(x^4-4)\\ | 5x^2-20&=5(x^4-4)\\ | ||
&= 5(x^2-2^2)\\ | &= 5(x^2-2^2)\\ | ||
- | &= 5(x+2)(x-2) | + | &= 5(x+2)(x-2)\,\textrm{.} |
- | \end{align} | + | \end{align}</math>}} |
- | </math> | + | |
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Current revision
If we take out the factor 5, we see that the expression can be factorized using the conjugate rule
\displaystyle \begin{align}
5x^2-20&=5(x^4-4)\\ &= 5(x^2-2^2)\\ &= 5(x+2)(x-2)\,\textrm{.} \end{align} |