Solution 2.1:3a

From Förberedande kurs i matematik 1

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m (Lösning 2.1:3a moved to Solution 2.1:3a: Robot: moved page)
Current revision (08:26, 23 September 2008) (edit) (undo)
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If we look at the expression, we see that it can be written as <math>x^2-6^2</math> and can therefore be factorized using the conjugate rule
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<!--center> [[Image:2_1_3a.gif]] </center-->
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If we look at the expression, we see that it can be written as <math>x^2-6^2</math> and can therefore be factorized using the conjugate rule.
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:<math> x^2-36=x^2-6^2=(x+6)(x-6).</math>
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{{Displayed math||<math> x^2-36=x^2-6^2=(x+6)(x-6)\,\textrm{.}</math>}}
Because the factors <math> x+6 </math> and <math> x-6 </math> are linear expressions, they cannot be factorized any further (as polynomial factors).
Because the factors <math> x+6 </math> and <math> x-6 </math> are linear expressions, they cannot be factorized any further (as polynomial factors).
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Current revision

If we look at the expression, we see that it can be written as \displaystyle x^2-6^2 and can therefore be factorized using the conjugate rule

\displaystyle x^2-36=x^2-6^2=(x+6)(x-6)\,\textrm{.}

Because the factors \displaystyle x+6 and \displaystyle x-6 are linear expressions, they cannot be factorized any further (as polynomial factors).